After the San Francisco 49ers’ home loss to the Los Angeles Rams, veteran tight end George Kittle wasn’t shying away from expectations. “We are incredibly talented, and we still have guys coming back,” Kittle said, maintaining confidence in a roster built for a deep run. “Mac’s been playing so well, so people are talking about controversy, but Brock’s an amazing quarterback, and that’s why we paid him so much money.”
Kittle, who has played in 12 postseason games across four years but still chases his first ring, believes this group has everything needed to compete again. “At some point, we’ll get Ricky and Brandon back,” he noted. “We have a lot of talent. We can score a ton of points, and I believe our defense will get a little bit better every single week.”
The 49ers have made the playoffs three times in the last five years, with their most recent deep run coming in 2023 when they reached Super Bowl LVIII before falling to the Chiefs. Despite the setback this season, Kittle’s message was clear, the 49ers aren’t backing down, and their playoff push is far from over.
Is there still a path to the playoffs for the 49ers this season?
The 49ers’ situation isn’t catastrophic; a 6-4 record is not the end of the world, but they must find a way to win more games. The recent crushing loss at home was painful and shattered the momentum they had built in Week 9 after winning on the road against the Giants.
Following the game against the Rams, the 49ers face three “easy” games before their NFL bye week: the Cardinals, Panthers, and Browns. These matchups should be perfect opportunities for Kittle and his teammates to secure wins and head into the break with a winning streak under their belts.

see also
George Kittle’s net worth: How much money does the San Francisco 49ers tight end have?
“If the 49ers manage to get to the playoffs it’s going to have to be 100% on the shoulders of the offense. Put up 30+ a game and hope to outlast. Luckily, they still have some very winnable games ahead,” wrote Dontay Atkinson of ReachNorth Media on X.





